In the first urn there are 3 white and 5 black balls, in the second 6 white and 4 black balls, in the third 1 white and 2 black balls.

In the first urn there are 3 white and 5 black balls, in the second 6 white and 4 black balls, in the third 1 white and 2 black balls. Throw the dice. If 1 or 2 falls out, then take the ball from the first urn. If it falls out 4, 5, 6, then take the ball from the third urn. Find the probability that a ball taken at random turns out to be white.

1) the probability of getting 1 or 2 = 1/3, that is, 33, (3)%
the probability of getting the white one = 3/8
that is, 1/3 × 3/8 = 1/8, that is, 12.5% is the probability of getting the white ball from the first basket.
2) the probability of a drop of 4, 5 or 6 = 1/2 (50%)
the probability of pulling out the white ball is 1/3. It turns out 1/2 × 1/3 = 1/6 or 16, (6)%
3) Add 12.5% + 16, (6)% ≈29.2% – the probability of pulling out the white ball.
Answer: 29.2%