In the interaction of 1.7 g of ammonia with hydrochloric acid, ammonium chloride weighing 5 g

In the interaction of 1.7 g of ammonia with hydrochloric acid, ammonium chloride weighing 5 g was obtained. Calculate the mass fraction of the yield of ammonium chloride.

The reaction of ammonia with hydrogen chloride is described by the following chemical reaction equation:

NH3 + HCl = NH4Cl;

When one mole of ammonia reacts with one mole of hydrochloric acid, one mole of ammonium chloride is formed.

Let’s find the available quantities of the substance.

M NH3 = 14 + 3 = 17 grams / mol;

N NH3 = 1.7 / 17 = 0.1 mol;

Let’s find the mass of the same amount of ammonium chloride.

M NH4Cl = 14 + 4 + 35.5 = 53.5 grams / mol;

m NH4Cl = 53.5 x 0.1 = 5.35 grams;

The mass fraction of the yield of ammonium chloride will be equal to the ratio of the masses of the practical and theoretical yields of the substance.

K = 5.00 / 5.35 = 0.9346 = 93.49%;