In the interaction of 100 liters of ammonia containing nitrogen impurities, the volume fraction of which

| September 8, 2021 | education

In the interaction of 100 liters of ammonia containing nitrogen impurities, the volume fraction of which is 10% with sulfuric acid, ammonium sulfate weighing 252 g was obtained, calculate the salt yield as a percentage of the theoretically possible

Given: V (NH3) = 100 l φ approx. = 10% m practical. ((NH4) 2SO4) = 252 g Find: ω out. ((NH4) 2SO4) -?
Solution: 1) Write the reaction equation: 2NH3 + H2SO4 => (NH4) 2SO4; 2) Find the volume fraction of pure NH3: φ (NH3) = 100% – φ approx. = 100% – 10% = 90%; 3) Find the volume of pure NH3: V (NH3) = φ (NH3) * V (NH3) / 100% = 90% * 100/100% = 90 l; 4) Find the amount of substance NH3: n (NH3) = V (NH3) / Vm = 90 / 22.4 = 4 mol; 5) Find the amount of substance (NH4) 2SO4: n ((NH4) 2SO4) = n (NH3) / 2 = 2 mol; 6) Find the theoretical mass (NH4) 2SO4: m theor. ((NH4) 2SO4) = n ((NH4) 2SO4) * Mr ((NH4) 2SO4) = 2 * 132 = 264 g; 7) Find the output (NH4) 2SO4: ω out. ((NH4) 2SO4) = m practical. ((NH4) 2SO4) * 100% / m theor. ((NH4) 2SO4) = 252 * 100% / 264 = 95%.
Answer: The yield of (NH4) 2SO4 was 95%.



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