In the interaction of 37 g of calcium hydroxide with ammonium sulfate, 15 g

In the interaction of 37 g of calcium hydroxide with ammonium sulfate, 15 g of ammonia were obtained. calculate the mass fraction of the ammonia yield.

The reaction of ammonium sulfate with calcium hydroxide is described by the following chemical reaction equation:

(NH4) 2SO4 + Ca (OH) 2 = 2NH3 + CaSO4 + 2H2O;

When interacting with one mole of calcium hydroxide, two moles of ammonia are formed.

Determine the amount of substance in 15 grams of calcium hydroxide.

M Ca (OH) 2 = 40 + 16 x 2 + 2 = 74 grams / mol;

N Ca (OH) 2 = 37/74 = 0.5 mol;

0.5 mol of calcium hydroxide will react to form 1 mol of ammonia.

Let’s find the theoretical mass of ammonia:

M NH3 = 14 + 3 = 17 grams / mol;

m NH3 = 1 x 17 = 17 grams;

The product yield will be equal to the ratio of practical and theoretical mass and will be:

K = 15/17 = 0.8823 = 88.23%;