In the interaction of 46 g of Na with water, practically 17.92 liters of hydrogen (H2)
| March 18, 2021 | education
In the interaction of 46 g of Na with water, practically 17.92 liters of hydrogen (H2) were obtained. Calculate the volume fraction of the reaction product yield.
2Na + 2H2O = 2NaOH + H2
n (Na) = 46/23 = 2 mol
but n (Na) = 2n (H2), therefore n (H2) = 1 mol
V (H2) = 22.4 * 1 = 22.4 liters
Output W (H2) = 17.92 / 22.4 = 0.8; = 80%
Answer: w output (H2) = 80%
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