in the interaction of magnesium oxide weighing 20 g with an excess of sulfur oxide

Given:

m (MgO) = 20 g;

To find:

m (MgSO4) -?

Decision:

MgO + SO3 = MgSO4, – we use the composed reaction equation to solve the problem:

1) Find the amount of magnesium oxide contained in 20 grams of the substance:

n (MgO) = m: M = 20 g: 40 g / mol = 0.5 mol;

2) We compose a logical expression:

if 1 mole of MgO gives 1 mole of MgSO4,

then 0.5 mol of MgO will give x mol of MgSO4,

then x = 0.5 mol.

3) Find the mass of magnesium sulfate formed during the reaction:

m (MgSO4) = n * M = 0.5 mol * 120 g / mol = 60 g.

Answer: m (MgSO4) = 60 g.