In the isosceles triangle ABC with the base AC, the non-signatures AE and CD are drawn.

In the isosceles triangle ABC with the base AC, the non-signatures AE and CD are drawn. Prove that triangle ADC = triangle CEA.

Since the triangle ABC is isosceles, the angle BAC = BCA.

Segments CD and AE of the bisector of equal angles at the base of the AC, then the angle EAC = DCA.

In triangles ADC and CEA, the AC side is common, angle DAC = ECA, angle EAC = DCA.

Then the triangles ADC and CEA are equal in side and two angles adjacent to it, as required.



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