In the isosceles triangle MNK with the base of the MN, the median KD is drawn.

In the isosceles triangle MNK with the base of the MN, the median KD is drawn. Find the angles of the leg holder KDM and the angle MKN, if the outer angle of the triangle MHK at the vertex H is 130 degrees.

Since the angles MHK and KHP are adjacent, the angle MHK = 180 – KHE = 180 – 130 = 50.

Since the triangle МKН is isosceles, then the angle KМН = МНK = 50, then the angle МKН = 180 – 50 – 50 = 80.

The median KD in an isosceles triangle is also the bisector and the height of the triangle, then the angle KDM = 90, the angle MKD = MKH / 2 = 80/2 = 40.

Answer: The angles of the KDM triangle are 50, 90, 40, the MCH angle is 80.