In the laboratory, it is necessary to fill a 1.5 liter can with oxygen. Can this be done if there is only 15.8 g of KMnO4?

Given:
V (cans) = 1.5 l.
m (KMnO4) = 15.8 g.
Decision:
1) n (KMnO4) = 15.8 / 158 = 0.1 mol
2) 2 KMnO4 = K2MnO4 + MnO2 + O2
3) n (O2) = 0.1 / 2 = 0.05 mol
4) V (O2) = 0.05 * 22.4 = 1.12 liters. – will not be enough
Answer: not enough



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