In the lake, at a depth of 30 m, a small fish with an area of 20 cm2 swims with what force the water presses on the fish

S = 20 cm2 = 0.002 m2.

h = 30 m.

g = 10 m / s2.

ρ = 1000 kg / m3.

F -?

The force of water pressure on the fish F is expressed by the formula: F = P * S, where P is the hydrostatic pressure of the water, S is the area of the fish.

The pressure of the liquid water Р is expressed by the formula: Р = ρ * g * h.

F = ρ * g * h * S.

F = 1000 kg / m3 * 10 m / s2 * 30 m * 0.002 m2 = 600 N.

Answer: the force of water pressure on the fish is F = 600 N.