In the metal oxide, the mass fraction of the trivalent metal is 52.94%. Find the formula for this oxide.

Let us denote the molar mass of the metal through x. Next, we use the following formula for the reaction.

W = M / M in-va * _100%.

Next, we substitute the formula.

W = 2x / (2x + 3 * 16).

(2x + 48) * 0.5294 = 2x.

Expand the brackets and perform the multiplication action.

1.0588 x + 25.4112 = 2 x.

2x – 1.0588 x = 25.4112.

0.9412 x = 25.4112

Let’s define the unknown value.

X = 25.4112 / 0.9412 = 26.99 g / mol.

Therefore, it is trivalent with a molecular weight of 26.99 g / mol.

Answer: This element is called aluminum oxide.



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