In the MPOK parallelogram, the MK side is 17 cm, on the OP side there is an OH segment equal to 6 cm.

In the MPOK parallelogram, the MK side is 17 cm, on the OP side there is an OH segment equal to 6 cm. Determine the type of the MPHK quadrangle and find the length of the AB segment, where points A and B are the midpoints of the MP and NC sides, respectively.

The MPHK is a trapezoid, since the PH is parallel to the MK (the opposite sides of the parallelogram are parallel).
Since A is the middle of the MR and B is the middle of the HK, then AB is the middle line of the trapezoid. AB = half sum of bases.
AB = (PH + MK) / 2 = ((17-6) +17) / 2 = (11 + 17) / 2 = 14.
Answer: MPHK is a trapezoid, AB = 14 cm.