In the orbit of what radius an artificial earth satellite is moving if its orbital speed is 8000 m / s.

Data: V (orbital velocity of the satellite in question) = 8000 m / s.

Constants: G (gravitational constant) = 6.67 * 10 ^ -11 m3 / (kg * s2); M (mass of the Earth) = 5.97219 * 10 ^ 24 kg;.

The orbital radius of the satellite in question is expressed from the formula: V2 = G * M / (R + h), whence Rо = R + h = G * M / V2.

Calculation: Ro = 6.67 * 10 ^ -11 * 5.97219 * 10 ^ 24/80002 ≈ 6224 * 10 ^ 3 km.

Answer: The orbit of the artificial satellite under consideration is 6224 * 10 ^ 3 km (Earth’s surface).



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