In the oscillatory circuit, the capacitance has increased 9 times. How will the period of natural oscillations of the circuit change?
| May 24, 2021 | education
To calculate the change in the period of natural oscillations of the specified circuit, we use the ratio: n = Tc / Tn = (2 * Π * √ (L * Cc)) / (2 * Π * √ (L * Cn)) = √ (Cc / Cn) …
The ratio of the variables: Cc (final capacity of the specified circuit) = Cn (initial capacity).
Calculation: n = √ (Cc / Cn) = √ (9Cn / Cn) = √9 = 3 p.
Answer: The period of natural oscillations of the specified circuit should have increased by 3 times.
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