In the oscillatory circuit, the capacitance of the capacitor is 0.1 μF.

| August 14, 2021 | education

In the oscillatory circuit, the capacitance of the capacitor is 0.1 μF. What inductance should a coil be to emit electromagnetic waves 94.2 km long?

To determine the required inductance of the coil used in the indicated oscillatory circuit, we use the equality: λ / Vc = T (period) = 2 * Π * √ (C * L), whence we express: L = λ ^ 2 / (Vc ^ 2 * 4 * Π2 * C).

Variables: λ – the required length of the emitted waves (λ = 94.2 km = 94.2 * 10 ^ 3 m); Vc is the speed of electromagnetic waves (Vc = 3 * 10 ^ 8 m / s); C is the capacitance of the capacitor (C = 0.1 μF = 0.1 * 10 ^ -6 F).

Let’s calculate: L = λ ^ 2 / (Vc ^ 2 * 4 * Π ^ 2 * C) = (94.2 * 10 ^ 3) ^ 2 / ((3 * 10 ^ 8) ^ 2 * 4 * 3, 14 ^ 2 * 0.1 * 10 ^ -6) = 0.025 H.

Answer: The coil of the indicated oscillatory circuit must have an inductance of 25 mH.



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