In the oscillatory circuit, the capacitance of the capacitor is 3 μF, and the maximum voltage across it is 4V.

In the oscillatory circuit, the capacitance of the capacitor is 3 μF, and the maximum voltage across it is 4V. Find the maximum magnetic field energy of the coil. Take active resistance equal to zero.

To calculate the value of the maximum energy of the magnetic field of the coil taken, we apply the formula: Wm = Wel = C * Um ^ 2/2.

Variables: C is the capacitance of the capacitor (C = 3 μF = 3 * 10 ^ -6 F); Um is the maximum voltage across the used capacitor (U = 4 V).

Let’s perform the calculation: Wm = C * Um ^ 2/2 = 3 * 10 ^ -6 * 4 ^ 2/2 = 24 * 10 ^ -6 J.

Answer: The maximum energy of the magnetic field of the taken coil is 24 μJ.