In the oscillatory circuit, the maximum value of the voltage across the capacitor is 120V. Determine the maximum current if the inductance of the coil is 5mH and the capacitance of the capacitor is 10mkF
Initial data: U (capacitor voltage value) = 120 V; L (coil inductance) = 5 mH (5 * 10 ^ -3 H); C (capacitance) = 10 μF (10 * 10 ^ -6 F).
The maximum current strength is determined using the law of conservation of energy: W = 0.5 * C * U ^ 2 = 0.5 * L * I ^ 2, whence I ^ 2 = C * U2 / L and I = √ (C * U ^ 2 / L).
Calculation: I = √ (10 * 10 ^ -6 * 120 ^ 2 / (5 * 10 ^ -3)) = 5.37 A.
Answer: The maximum amperage is 5.37 A.
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