In the parallelogram abcd, the angle b is equal to 150 sides of the parallelogram 18 cm, 19 cm.

In the parallelogram abcd, the angle b is equal to 150 sides of the parallelogram 18 cm, 19 cm. Find the area of the parallelogram.

We will draw from the top B to the height of the ВН.
The sum of the adjacent angles of the parallelogram is 180, then the angle ABD = 180 – 150 = 30, then the leg BН lies opposite the angle 30, and is equal to half the length of AB. ВН = AB / 2 = 18/2 = 9 cm.
Then Savsd = AD * BH = 19 * 9 = 171 cm2.
Answer: The area of the parallelogram is 171 cm2.



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