In the parallelogram ABCD, the diagonal AC and the sides AD and CD form angles of 30 degrees and 45 degrees
| June 23, 2021 | education
In the parallelogram ABCD, the diagonal AC and the sides AD and CD form angles of 30 degrees and 45 degrees, respectively. Find the degree measure of angle A.
Angle BAC = ACD as criss-crossing angles at the intersection of parallel lines AB and CD of the secant AC.
Then the angle BAD = BAC + CAD = 30 + 45 = 75.
Answer: The degree measure of angle A is 75.
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