In the parallelogram ABCD, the diagonals intersect at point O, K is the middle of the side AD, AK = 5cm

univerkov | August 9, 2021 | education

In the parallelogram ABCD, the diagonals intersect at point O, K is the middle of the side AD, AK = 5cm, KO = 6cm Find the perimeter of the parallelogram ABCD.

Since point K is the middle of the side AD, then AK = DK = 5 cm, then AD = 2 * AK = 2 * 5 = 10 cm.

Since the diagonals of the parallelogram at the intersection point O are divided in half, point O is the middle of the diagonal BD, and since point K is the middle of the side AD, then the segment OK is the middle line of the triangle ABD, and then AB = 2 * OK = 2 * 6 = 12 cm …

Determine the perimeter of the parallelogram ABCD.

Ravsd = 2 * (AB + AD) = 2 * (12 + 10) = 44 cm.

Answer: The perimeter of the parallelogram is 44 cm.

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