In the parallelogram abcd, the diagonals intersect at point o, k is the middle of the side ad

In the parallelogram abcd, the diagonals intersect at point o, k is the middle of the side ad, ak = 5 cm, ko = 6 cm, find the perimeter.

Since point K is the middle of the base AD, and point O is the middle of the diagonal BD, since the diagonals at the intersection point are divided in half, the segment OK is the middle line of the triangle ABD and is equal to half the length of AB, then AB = OK * 2 = 6 * 2 = 12 cm.

Length АD = 2 * AK = 2 * 2 = 10 cm.

Determine the perimeter of the parallelogram. Pavsd = 2 * (AB + AD) = 2 * (12 + 10) = 44 cm.

Answer: The perimeter of the parallelogram is 44 cm.



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