In the parallelogram ABCD, the diagonals intersect at point O. The adjacent sides of the parallelogram are 10 cm and 15 cm.Find the difference between the perimeters of triangle AOB and triangle AOD
The perimeter of the triangle AOB = AB + BO + AO.
The perimeter of the triangle AOD = AD + OD + AO.
Since ABCD is a parallelogram, then the diagonal BD is divided by point O in half, then BO = DO.
Raov = 10 + ВO + AO.
Raod = 15 + ВO + AO.
Raod – Raov = (15 + ВO + AO) – (10 + ВO + AO) = 15 – 10 = 5 cm.
Answer: The difference in the perimeter of the triangles is 5 cm.
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