In the parallelogram ABCD, the height lowered to the CD side divides it in half and

In the parallelogram ABCD, the height lowered to the CD side divides it in half and forms an angle of 30 degrees with the BC side, AB = 26 cm. Find the perimeter

In a parallelogram, the lengths of the opposite sides are equal, CD = AB = 26 cm.

By condition, the HВ Height divides the СD in half, then CH = DН = СD / 2 = 26/2 = 13 cm.

In a right-angled triangle BCН, the CH leg lies opposite an angle of 300, then BC = AD = 2 * CH = * 13 = 26 cm.

Determine the perimeter of the parallelogram. Ravsd = 2 * (AB + BC) = 2 * (26 + 26) = 2 * 52 = 104 cm.

Answer: The perimeter of the parallelogram is 104 cm.