In the parallelogram BCDE, the diagonals intersect at point M. It is known that BC = 4 cm

In the parallelogram BCDE, the diagonals intersect at point M. It is known that BC = 4 cm, CE = 10 cm, BD = 12 cm. Find the perimeter of the DME triangle.

According to the parallelogram property, its diagonals at the intersection point are divided in half, then CM = EM = 10/2 = 5 cm, BM = DM = 12/2 = 6 cm.

In a parallelogram, the opposite sides are equal, then DE = BC = 4 cm.

Determine the perimeter of the DME triangle. Rdme = DM + EM + DE = 6 + 5 + 4 = 15 cm.

Answer: The perimeter of the DME triangle is 15 cm.



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