In the press, the area of the large piston is 1500 cm2, and the area of the small piston is 2 cm2.

In the press, the area of the large piston is 1500 cm2, and the area of the small piston is 2 cm2. A force of 100 N acts on the small one. Determine the pressure force produced by the large piston.

Since the pressure of the liquid in the pistons of the press is the same, then the ratio will be true:

F1 / S1 = F2 / S2, where F1 is the pressure force produced by the large piston (N), S1 is the surface area of the larger piston (S1 = 1500 cm2 = 1500 * 10-4 m2), F2 is the pressure force produced by the smaller piston ( F2 = 100 N), S2 is the surface area of the small piston (S2 = 2 cm2 = 2 * 10-4 m2).

F1 = F2 * S1 / S2 = 100 * 1500 * 10-4 / 2 * 10-4 = 75000 N = 75 kN.

Answer: The pressure force is 75 kN.