In the process of expanding the gas from a volume of 0.3 m3 to 0.7 m3, work of 400 J

In the process of expanding the gas from a volume of 0.3 m3 to 0.7 m3, work of 400 J was perfect, at what pressure was the gas, if it did not change during the work?

To determine the gas pressure in the indicated isobaric expansion, we apply the formula: A = P * ΔV, whence we express: Р = А / ΔV = А / (Vк – Vн).

Variables: A – perfect work (A = 400 J); Vк – volume after expansion (Vк = 0.7 m3); Vн – initial volume (Vн = 0.3 m3).

Calculation: P = A / (Vk – Vn) = 400 / (0.7 – 0.3) = 10 ^ 3 Pa.

Answer: The gas in the indicated isobaric expansion was at a pressure of 1 kPa.