In the process of nuclear fusion of 10,000 kg of hydrogen, 9644 kg of helium were formed.

In the process of nuclear fusion of 10,000 kg of hydrogen, 9644 kg of helium were formed. How much energy was released during this?

Decision:
m3 = 356 kg
E = mc2 = 356 * 3 * 10 (16th degree) = 1068 * 10 (16th degree) J
Answer: 1068 * 10 (to the 16th degree) J



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