In the process of photosynthesis, the plant absorbed 168 liters of carbon dioxide. How much glucose

In the process of photosynthesis, the plant absorbed 168 liters of carbon dioxide. How much glucose can be produced in this case? How much oxygen will be released?

1. Let’s write the equation of chemical interaction:

6CO2 + 6H2O = C6H12O6 + 6O2.

2. Calculate the chemical number of carbon dioxide (Vm – molar volume equal to 22.4 l / mol):

n (CO2) = V (CO2) / Vm = 168 l / 22.4 l / mol = 7.5 mol.

3. Using the equation of the chemical reaction, we find the mass of glucose and the volume of oxygen:

n (C6H12O6) = n (CO2) / 6 = 7.5 mol / 6 = 1.25 mol.

m (C6H12O6) = n (C6H12O6) * M (C6H12O6) = 1.25 mol * 180 g / mol = 225 g.

n (O2) = n (CO2) = 7.5 mol.

V (O2) = n (O2) * Vm = 7.5 mol * 22.4 L / mol = 168 L.

Answer: m (C6H12O6) = 225 g; V (O2) = 168 l.