In the quadrilateral ABCD O is the intersection of the diagonals and BC = AD AB = CD AC = 16cm
| June 16, 2021 | education
In the quadrilateral ABCD O is the intersection of the diagonals and BC = AD AB = CD AC = 16cm BD = 14cm the perimeter of the triangle AOB is 25 cm Find AB.
Since, by condition, AB = CD, BC = AD, then the quadrilateral ABCD is a parallelogram.
The diagonals of the parallelogram are divided in half at the point of intersection, then AO = AC / 2 = 16/2 = 8 cm, OB = BD / 2 = 14/2 = 7 cm.
Raov = (AB + BO + AO).
AB = Raov – BО – AO = 25 – 7 – 8 = 10 cm.
Answer: The length of the AB side is 10 cm.
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