In the quadrilateral ABCD, side AB is 15 cm less than BC, and side AD is 30 cm larger

In the quadrilateral ABCD, side AB is 15 cm less than BC, and side AD is 30 cm larger than CD. What is the perimeter of this quadrilateral if AB = CD = 16 cm?

AB = CD = 16 cm;

AB is less than BC by – 15 cm;

АD is more than СD by – 30 cm;

Find the perimeter of the quadrilateral.

To do this, we must find the side BC and AD, then find the perimeter.

BC = 16 + 15 = 31 cm;

AD = 16 + 30 = 46 cm;

16 + 16 + 31 + 46 = 109 cm

Answer: The perimeter of the quadrangle is 109 cm.



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