In the reaction BaCl2 + Cl2 = BaCl2, 5 kg of barium chloride was formed. What mass of chlorine reacted with barium?

1. We write down the equation of the reaction of chlorine with barium:

Ba + Cl2 = BaCl2.

2. Find the chemical amount of barium chloride:

n (BaCl2) = m (BaCl2): M (BaCl2);

M (BaCl2) = 137 + 35.5 * 2 = 208 g / mol;

n (BaCl2) = 5000: 208 = 24.038 mol.

3. Determine the amount of reacted chlorine:

n (Cl2) = n (BaCl2) = 24.038 mol.

4. Let’s calculate the mass of chlorine:

m (Cl2) = n (Cl2) * M (Cl2) = 24.038 * 71 = 1707 g or 1.7 kg.

Answer: 1.7 kg.