1. We write down the equation of the reaction of chlorine with barium:
Ba + Cl2 = BaCl2.
2. Find the chemical amount of barium chloride:
n (BaCl2) = m (BaCl2): M (BaCl2);
M (BaCl2) = 137 + 35.5 * 2 = 208 g / mol;
n (BaCl2) = 5000: 208 = 24.038 mol.
3. Determine the amount of reacted chlorine:
n (Cl2) = n (BaCl2) = 24.038 mol.
4. Let’s calculate the mass of chlorine:
m (Cl2) = n (Cl2) * M (Cl2) = 24.038 * 71 = 1707 g or 1.7 kg.
Answer: 1.7 kg.
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