In the reaction between aluminum and graphite, 4 mol of the product al4c3 was obtained and 832 kJ

In the reaction between aluminum and graphite, 4 mol of the product al4c3 was obtained and 832 kJ of heat was released. What is the thermal effect of the reaction?

1. Let us write the equation of the ongoing thermochemical process:

4Al + 3C = Al4C3 + Q;

2. Let’s make the proportion:

when 1 mol of Al4C3 is formed, x kJ of heat is released;

with the formation of 4 mol of Al4C3 – 832 kJ;

3. Let’s calculate the heat effect of the reaction:

x = 1 * 832: 4 = 208 kJ.

Answer: 208 kJ.