In the reaction Fe2O3 + 6HCl = 2FeCl3 + 3H2O, determine the amount of the reagent

In the reaction Fe2O3 + 6HCl = 2FeCl3 + 3H2O, determine the amount of the reagent Fe2O3 required to obtain 0.72 mol of the product FeCl3.

In this task, we will determine the mass of iron oxide required to obtain ferric chloride.

We write down the reaction equation.

Fe2O3 + 6HCl = 2FeCl3 + 3H2O.

Using the reaction equation, we determine the amount of iron oxide substance.

X mol Fe2O3 – 0.72 mol FeCl3.

1 mol Fe2O3 – 2 mol FeCl3.

Let’s define the unknown value of x.

X = 1 * 0.72: 2 = 0.36 mol.

Next, you need to determine the mass of iron oxide.

M (Fe2O3) = 56 * 2 + 16 * 3 = 112 + 48 = 160 g / mol.

Next, let’s define the mass.

m = 0.36 mol * 160 g / mol = 57.6 g.

Answer: the mass is 57.6 g.