In the reaction Mg + O2 = MgO, 500 mg of magnesium oxide was formed. What volume of oxygen reacted with magnesium?
March 5, 2021 | education
| The combustion reaction of magnesium is described by the following chemical reaction equation:
2Mg + O2 = 2MgO;
To obtain two moles of magnesium oxide, one mole of oxygen is required.
Let’s determine the amount of substance in 12 grams of magnesium oxide.
M MgO = 24 + 16 = 40 grams / mol;
N MgO = 12/40 = 0.3 mol;
Let us determine the volume (n.v.) and the number of oxygen molecules.
N O2 = N MgO / 2 = 0.3 / 2 = 0.15 mol;
Under normal conditions, one mole of ideal gas takes up a volume of 22.4 liters.
The oxygen volume will be:
V O2 = 0.15 x 22.4 = 3.36 liters;
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