In the reaction of aluminum with sulfuric acid, 3.42 g of aluminum sulfate was formed.

In the reaction of aluminum with sulfuric acid, 3.42 g of aluminum sulfate was formed. Determine the mass and amount of aluminum reacted?

Let’s compose the equation for the reaction of interaction of aluminum with sulfuric acid:
2Al + 3H2SO4 = Al2 (SO4) 3 + 3H2;

Find the molecular weight of aluminum sulfate:
27 * 2 + 3 * 32 + 12 + 16 = 342 g / mol;

Let’s find the amount of substance in aluminum sulfate:
3.42 / 342 = 0.01 mol;

Before aluminum there is a coefficient 2 times higher than before aluminum sulfate. This means that the amount of substance in aluminum is 0.02 mol. Let’s find the mass of aluminum:
0.02 * 27 = 0.54 grams;

Answer: the amount of substance in aluminum is 0.02 mol, the mass of aluminum is 0.54 grams.