In the reaction of glycerin with sodium, the chemical amounts of which are 1: 1

In the reaction of glycerin with sodium, the chemical amounts of which are 1: 1, hydrogen was formed with a chemical amount of 0.18 mol. Determine the chemical amount of glycerin that reacted.

Given:
n (C3H5 (OH) 3): n (Na) = 1: 1
n (H2) = 0.18 mol

Find:
n (C3H5 (OH) 3) -?

Solution:
1) Write the equation of a chemical reaction:
C3H5 (OH) 3 + Na => C3H5 (OH) 2 (ONa) + 0.5H2 ↑;
2) Find the amount of substance C3H5 (OH) 3 (taking into account the coefficients in the reaction equation):
n (C3H5 (OH) 3) = n (H2) * 1 / 0.5 = 0.18 * 1 / 0.5 = 0.36 mol.

Answer: The amount of substance C3H5 (OH) 3 is 0.36 mol.