In the reaction of interaction of methane with 4.75 liters of chlorine, chloromethane was released.
| December 8, 2020 | education
In the reaction of interaction of methane with 4.75 liters of chlorine, chloromethane was released. Calculate the mass of the obtained chloromethane CH3Cl
CH4 + Cl2 = CH3Cl + HCl
1) n (Cl2) = V / Vm = 4.75 / 22.4 = 0.2 mol
2) n (CH3Cl) = n (Cl2) = 0.2 mol
3) n = m / M, m = n * M
m (CH3Cl) = 0.2 * 50.5 = 10.1 grams
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