In the reaction of magnesium with sulfuric acid, 120 g was formed. magnesium sulfate.

In the reaction of magnesium with sulfuric acid, 120 g was formed. magnesium sulfate. Determine the amount of magnesium that has reacted.

Given:

m (MgSO4) = 120g / mol.

n (MgSO4) -?

Decision:

Find the amount of magnesium sulfate substance by the formula:

n = m: M.

M (MgSO4) = 24 + 32 + 64 = 120 g / mol.

n = 120 g: 120 g / mol = 1 mol.

Let’s compose the reaction equation, find the quantitative ratios of substances.

Mg + H2SO4 = MgSO4 + H2 ↑.

According to the reaction equation, there is 1 mol of magnesium for 1 mol of magnesium sulfate. Substances are in quantitative ratios 1: 1.

The amount of magnesium and magnesium sulfate will be equal.

n (Mg) = n (MgSO4) = 1 mol.

Answer: 1 mole.