In the reaction of zinc with hydrochloric acid, 1.6 g of zinc chloride was formed. Calculate the mass of the amount

In the reaction of zinc with hydrochloric acid, 1.6 g of zinc chloride was formed. Calculate the mass of the amount of zinc reacted.

1.Let’s find the amount of zinc chloride substance by the formula:

n = m: M.

M (ZnCl2) = 65 + 70 = 135g / mol.

n = 1.6 g: 135 g / mol = 0.012 mol.

2. Make up the reaction equation. We determine in what quantitative ratios the substances are.

Zn + 2HCl = ZnCl2 + H2.

For 1 mole of zinc there is 1 mole of zinc chloride. The substances are in quantitative ratios of 1: 1. The amount of zinc and zinc chloride will be the same.

n (Zn) = n (ZnCl2) = 0.012 mol.

3.Let’s find the mass of zinc by the formula:

m = n M,

M (Zn)) = 65 g / mol.

m = 0.012 mol × 65 g / mol = 0.78 g.

Answer: 0.78 g.