In the rectangle ABCD, BD = 16 cm, CD = 13 cm, O is the point of intersection of the diagonals.

In the rectangle ABCD, BD = 16 cm, CD = 13 cm, O is the point of intersection of the diagonals. Find the perimeter of triangle AOB.

A rectangle is a quadrilateral in which opposite sides are equal in pairs, and all corners are straight:

AB = CD = 13 cm;

BC = AD.

The diagonals of the rectangle are equal to each other, and the point of their intersection is halved. Thus:

AC = BD = 16 cm;

AO = OS = BO = OD = 16/2 = 8 cm.

The perimeter of a triangle is the sum of all its sides. To calculate the perimeter of the triangle ΔAOB, consider it.

PAOB = AO + OB + AB;

RAOB = 8 + 8 + 13 = 29 cm.

Answer: the perimeter of the triangle ΔAOB is 29 cm.