In the rhombus ABCD, the angle ABC = 140 degrees. Find the angles of the triangle AOB (O intersection point of the diagonals).

A rhombus is a quadrilateral in which all sides are equal and opposite sides are parallel.
The diagonals of the rhombus are bisectors, that is, they divide the angle in half and form right angles when they intersect.
Consider the triangle AOB, which was formed at the intersection of the diagonals of the rhombus.
1. The AВO angle is 140/2 = 70 degrees.
2. The BOA angle is 90 degrees.
3. The angle of the BOA is 180 – (70 + 90) = 180 – 160 = 20 degrees.
Answer: Angle ABO = 70 degrees, angle BOA = 90 degrees, angle BAO = 20 dus.