In the rhombus ABCD, the angle ACB = 65. Find the angle CDA.
| February 18, 2021 | education
Since the diagonals of the rhombus are the bisectors of the angles at its vertices, they divide these angles in half, then the angle ВСD = 2 * ACB = 2 * 65 = 130.
The sum of the adjacent angles of the rhombus is 1800, the angle СDA + ВСD = 180.
Then the angle СDA = 180 – ВСD = 180 – 130 = 50.
Answer: The СDA angle is 50.
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