In the rhombus ABCD, the diagonals intersect at point O, the angle of the BCD is 48 degrees
| February 9, 2021 | education
In the rhombus ABCD, the diagonals intersect at point O, the angle of the BCD is 48 degrees, find the angle of the triangle AOB.
The sum of the adjacent angles of the rhombus is 1800, then the angle ABC = 180 – ВСD = 180 – 48 = 132.
The diagonals of the rhombus divide the angles at the vertices in half, then the angle ABO = ABC / 2 = 132/2 = 66.
ВАО angle = ВAD / 2 = 48/2 = 24.
At the rhombus, the diagonals intersect at right angles, then the angle AOB = 90.
Answer: The angles of the AOB triangle are 24, 66, 90.
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