In the rhombus ABCD, where O is the point of intersection of the diagonals BD and AC, the angle AD

In the rhombus ABCD, where O is the point of intersection of the diagonals BD and AC, the angle AD is equal to 110 degrees. Find the angles of the triangle AOB?

ABSD is a rhombus, hence the opposite angles are equal and the diagonals are the bisectors of its corners. The diagonals of the rhombus intersect at right angles, so triangle AOB is right-angled.

angle AOB = 90;

angle ABO = (angle ABC) / 2 = 110/2 = 55;

angle BAO = 90 – angle ABO = 90 – 55 = 35;

Answer: 90, 55, 35.