In the section of the circuit, the current strength is 2 A, the resistance across the resistor is 4 ohms.

In the section of the circuit, the current strength is 2 A, the resistance across the resistor is 4 ohms. Determine the work of the current when passing through the conductor in 10 s.

I = 2 A.

R = 4 ohms.

t = 10 s.

A -?

The work of electric current A in a conductor is determined by the formula of the Joule-Lenz law: A = I * U * t, where I is the current in the conductor, U is the voltage at the ends of the conductor, t is the time the current passes through the conductor.

We express the voltage at the ends of the conductor U from Ohm’s law for the section of the circuit: U = I * R, where R is the resistance of the conductor.

The Joule-Lenz law will take the form: A = I ^ 2 * R * t.

A = (2 A) ^ 2 * 4 Ohm * 10 s = 160 J.

Answer: the work of the current in the conductor is A = 160 J.