In the series of chemical elements Si – P – S – Cl from left to right: 1) the radius of the atom increases

In the series of chemical elements Si – P – S – Cl from left to right: 1) the radius of the atom increases 2) the number of energy levels increases 3) the charges of atomic nuclei decrease 4) the number of electrons at the outer level increases.

In the series of chemical elements, Si – P – S – Cl are in one third period from left to right.

1. The first statement is false. In the periodic table, the size of atoms decreases diagonally from francium (Fr) to fluorine (F). Therefore, from left to right, for elements of the same period, the atomic radii decrease.

2. The second statement is false. Elements that are in the same period have the same number of energy levels, their number is equal to the number of the period. For elements Si – P – S – Cl, the number of energy levels is the same and is equal to three, the number of the period.

3. The third statement is false. On the charge of an atom, the number of protons indicates the ordinal number of the element. For elements Si – P – S – Cl they are equal to 14, 15, 16, 17, respectively. We see that the number of charge of the atom increases.

4. The fourth statement is correct. The number of electrons on the outer level increases. The number of electrons in an element is equal to the number of charge of atoms or an ordinal number. For elements Si – P – S – Cl, they are equal to 14, 15, 16, 17, respectively. This means that the number of electrons at the outer level increases:

Si – 1S²2P⁶3S²3P⁴

P – 1S²2P⁶3S²3P⁵

S – 1S²2P⁶3S²3P6

CL – 1S²2P⁶3S²3P⁷