In the solenoid, the magnetic flux in 10 ms uniformly changed from 2×10-7 Wb to 6×10-7.

In the solenoid, the magnetic flux in 10 ms uniformly changed from 2×10-7 Wb to 6×10-7. Determination of the number of turns in a solenoid if the EMF in it is 2 V.

To calculate the number of turns in the indicated solenoid, we apply the formula: ε = N * (Фк – Фн) / Δt, whence N = ε * Δt / (Фк – Фн).
Variables: ε – EMF in the indicated solenoid (ε = 2 V); Δt – time change (Δt = 10 ms = 0.01 s); Фк – final magnetic flux (Фк = 6 * 10 ^ -7 Vb); Фн – initial magnetic flux (Фн = 2 * 10 ^ -7 Vb).
Let’s make the calculation: N = ε * Δt / (Фк – Фн) = 2 * 0.01 / (6 * 10 ^ -7 – 2 * 10 ^ -7) = 50 * 10 ^ 3 turns.
Answer: The indicated solenoid contains 50 * 10 ^ 3 turns.