In the steam heating radiator 5 kg of steam condensed at 100 °. How much heat was released during this?

univerkov | February 5, 2021 | education

To find out the heat obtained during condensation of steam in the specified radiator, consider the formula: Qx = Lp * mp, where Lp – beats. heat of condensation of steam (Lp = 2256.2 * 10 ^ 3 J / kg); mп – mass of condensed steam (mp = 5 kg).

Let’s perform the calculation: Qx = Lp * mp = 2256.2 * 10 ^ 3 * 5 = 11281 * 10 ^ 3 J ≈ 11.3 MJ.

Answer: During the condensation of steam in the specified radiator, 11.3 MJ of heat was obtained.

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