In the three vertices of a square with a side of 1 m, there are positive point charges

In the three vertices of a square with a side of 1 m, there are positive point charges of 10 ^ -7cl. determine the field strength at the center of the square

Tension E:

E = E1 + E2 + E3, where E1, E2, E3 are tensions created by each charge separately.

The charges, which are located at diagonally opposite points of the square at point O, compensate for each other’s action. Each of them individually will create a field of the same intensity, but their directions will be opposite:

E1 + E3 = 0;

E = E2.

Find the distance r from the vertex to the center O of the square. It will be equal to half the diagonal of a square with side a = 1 m:

r = d / 2 = √ (a ^ 2 + a ^ 2) / 2 = (a√2) / 2 = (√2 / 2) m.

E = kq / r ^ 2 = (9 * 10 ^ 9 (H * m ^ 2) / Kl ^ 2 * (10 ^ (- 7) Kl)) / ((√2 / 2) m) ^ 2 =
= 2 * 9 * 10 ^ 2 C / m ^ 2 = 1.8 * 10 ^ 3 N / C = 1.8 * 10 ^ 3 V / m.

Answer: 1.8 * 10 ^ 3 V / m.