In the trapezium ABCD, it is known that AB = CD, the angle BDA = 30 degrees and the angle BDC

In the trapezium ABCD, it is known that AB = CD, the angle BDA = 30 degrees and the angle BDC = 110 degrees. Find the ABD angle.

1. Let us determine the value of the angle CDA of the trapezoid ABCD, since the angles BDA and BDC are known.

110 + 30 = 140 °.

2. The angle BAD is equal to the angle CDA, as are the angles at the base of an isosceles trapezoid, that is, 140 °.

3. Let’s calculate how many degrees is the angle ABD.

180 – (140 + 30) = 10 °.

Answer: 10 °.



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